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Question:
find the equation of parabola whose focus is (3,0) and directrix is 3x 4y=1
Answer:

Given focus S(3, 0)

and equation of directrix is:  3x + 4y = 1

=> 3x + 4y - 1 = 0

Let P (x, y) be any point on the required parabola and let PM be the length of the perpendicular from P on the directrix

Then, SP = PM

=> SP2 = PM2

=> (x - 3)2 + (y - 0)2 = {(3x + 4y - 1) /{√(32 + 42 )}2

=> x2 + 9 - 6x + y2 = (9x2 + 16y2 + 1 + 24xy - 8y - 6x)/25

=> 25(x2 + 9 - 6x + y2 ) = 9x2 + 16y2 + 1 + 24xy - 8y - 6x

=> 25x2 + 225 - 150x + 25y2 = 9x2 + 16y2 + 1 + 24xy - 8y - 6x

=> 25x2 + 225 - 150x + 25y2 - 9x2 - 16y2 - 1 - 24xy + 8y + 6x = 0

=> 16x2 + 9y2 - 24xy - 144x + 8y + 224 =

This is the required equation of parabola.

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