Given, parabola is x² = 9y

Let P(h, k) is the point on the parabola such that abscissa is 3 times the ordinate.

So, h = 3k   .........1

Since P(h, k) lies on the parabola

So, h² = 9k .........2

From equation 1 and 2, we get

    (3k)² = 9k

=> 9k² = 9k

=> 9k² - 9k = 0

=> 9k(k - 1) = 0

=> k = 0, 1

When k = 0, h = 0

So k = 1

Now, from equation 1,

h = 3 * 1 = 3

So, the point is (3, 1)