Question:
Find the equation to the circle which touches x = 0,y = 0 and d = 2 is
Answer:
The diameter of the circle = 2 - 0 = 2
So, radius of the circle = 2/2 = 1
Now, the coordinates of the center is (1, 1)
Hence, equation of the circle is
(x - 1)2 +(y - 1)2 = 12
=> (x - 1)2 +(y - 1)2 = 1
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