Given complex number = √3 - i

Polar form of a complex number = r(cosθ + i*sinθ)

Now r*cosθ = √3  ...........1

      r*sinθ = -1  ..............2

square equation 1 and 2 and add them, we get

r² * (cos² θ + sin² θ) = (√3)² + (-1)²

r² = 3 + 1

r² = 4

r = √4

r = +2, -2

Again divide equation 2 by equation 1, we get

(r*sinθ)/(r*cosθ) = -1/√3

tanθ = -1/√3

θ = tan^-1 (-1/√3)

θ = -Π/6