

If the complex numbers y2 x- 5i and 4 + i(x + y2 ) are conjugate to each other then find real values of x & y.
Given, the complex numbers y2 x - 5i and 4 + i(x + y2 ) are conjugate to each other.
=> y2 x - 5i and 4 - i(x + y2 )
On comparing real and imaginary part, we get
y2 x = 4 ............1
x + y2 = 5 .........2
From equation 1, we get
x = 4/y2 ............3
Put value of x in equation 2, we get
4/y2 + y2 = 5
=> (4 + y4 )/y2 = 5
=> 4 + y4 = 5 * y2
=> y4 - 5y2 + 4 = 0
=> y4 - 4y2 - y2 + 4 = 0
=> y2 (y2 - 4) - 1(y2 - 4) = 0
=> (y2 - 4) * (y2 - 1) = 0
=> y2 = 4, 1
=> y = ±2, ±1
Put value of y in equation 1, we get
x = 4/(±2)2 and x = 4/(±1)2
=> x = 4/4 and x = 4
=> x = 1, 4
Hence, when y = ±2, x = 1
and when when y = ±1, x = 4
