learnohub
Question:

If the complex numbers y2 x- 5i and 4 + i(x + y2 ) are conjugate to each other then find real values of x & y.
 
   

Answer:

Given, the complex numbers y2 x - 5i and 4 + i(x + y2 ) are conjugate to each other.

=> y2 x - 5i and 4 - i(x + y2 )

On comparing real and imaginary part, we get

y2 x = 4   ............1

x + y2 = 5  .........2

From equation 1, we get

x = 4/y2   ............3

Put value of x in equation 2, we get

      4/y2 + y2 = 5

=> (4 + y4 )/y2 = 5

=> 4 + y4 = 5 * y2

=> y4 - 5y2 + 4 = 0

=> y4 - 4y2 - y2 + 4 = 0

 => y2 (y2 - 4) - 1(y2 - 4) = 0

=> (y2 - 4) * (y2 - 1) = 0

=> y2 = 4, 1

=> y = ±2, ±1

Put value of y in equation 1, we get

      x = 4/(±2)2 and x = 4/(±1)2

=> x = 4/4 and x = 4

=> x = 1, 4

Hence, when y = ±2, x = 1

and when when y = ±1, x = 4
    

Not what you are looking for? Go ahead and submit the question, we will get back to you.

learnohub

Classes

  • Class 6
  • Class 7
  • Class 8
  • Class 9
  • Class 10
  • Class 11
  • Class 12
  • ICSE 6
  • ICSE 7
  • ICSE 8
  • ICSE 9
  • ICSE 10
  • NEET
  • JEE

YouTube Channels

  • LearnoHub Class 11,12
  • LearnoHub Class 9,10
  • LearnoHub Class 6,7,8
  • LearnoHub Kids

Overview

  • FAQs
  • Privacy Policy
  • Terms & Conditions
  • About Us
  • NGO School
  • Contribute
  • Jobs @ LearnoHub
  • Success Stories
© Learnohub 2026.