Question:
2cos* = 1
cos*=1/2
* = pie/3 how its possible
another one
cos* = 1/2
* = 2pie/3 how its possible i am not able to understand this in you third vedio of complex number
Answer:
Given, 2 * cos x = 1
=> cos x = 1/2
=> cos x = cos π/3
=> x = π/3
Again, in generel form
x = 2nπ ± π/3, where n ∈ Z
Let x = 2nπ - π/3 , n = 1
=> x = 2π - π/3
=> x = (2*3π - π)/3
=> x = (6π - π)/3
=> x = 5π/3
So, x = π/3, 5π/3 ∈ [0, 2π]
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