Question:
(1+ i)(1+ 2i)
Answer:
Given, (1 + i)*(1 + 2i)
= 1 + 2i + i + i * 2i
= 1 + 3i + 2i2
= 1 + 3i - 2 {since i2 = -1}
= 3i - 1
So, (1 + i)*(1 + 2i) = 3i - 1
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Given, (1 + i)*(1 + 2i)
= 1 + 2i + i + i * 2i
= 1 + 3i + 2i2
= 1 + 3i - 2 {since i2 = -1}
= 3i - 1
So, (1 + i)*(1 + 2i) = 3i - 1