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Given, (i - 1)*(2 - i)
= 2i - i2 - 2 + i
= 2i - (-1) - 2 + i {Since i2 = -1 }
= 2i + 1 - 2 + i
= 3i - 1
Now, absolute value of 3i - 1 = √{32 + (-1)2 }
= √{9 + 1}
= √10
So, the absolute value of (i - 1)*(2 - i) = √10