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We know that
nCr = n!/{(n - r)! * r!) where n ≥ r
Now, 4C2 = 4!/{(4 - 2)! * 2!}
= 4!/(2! * 2!)
= (4 * 3 * 2 * 1)/(2 * 1 * 2 * 1) {n! = n*(n-1)*(n-2)*........3*2*1}
= 24/4
= 6
In this way, we find the value.