Question:
the no of atoms in 20gof SO3 is
Answer:
Number of present in 20 gm of SO3 = 20/80.07 = 0.25 mol
Therefore, Number of molecules present in 20 gm of SO3 = 0.25 x 6.022 x1023 =1.5 x1023 molecule
Each SO3 molecule has four atoms
Hence, total number of atoms in 20 gm of SO3 = 1.5 x1023 x 4 = 6 x1023 atoms
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