Question:
how many water molecules are present in18kg of water
Answer:
18 gms of water = 1 mole
18 kgs (18 x 1000 g) of water = 1000 moles
So, 1 mole = 6.023 x 1023 molecules,
1000 moles = 6.023 x 1023 x 1000 = 6.023 x 1026 molecules are present in 18 kg of water.
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