Question:
exprement no. 1= 0.243g Mg on burning with O2 yield 0.4030g of mgo.
exprement no. 2= 0.182g of Mg burning with O2 yield 0.302g MgO.
prove by law of definite proportion .
Answer:
Experiment 1: Weight of Magnesium oxide =0.4030 gm
Weight of Magnesium =0.2430 gm
Weight of oxygen=0.4030–0.2430=0.16 gm
Ratio of Magnesium: oxygen =0.2430:0.16=1.552:1
Experiment 2:
Weight of Magnesium oxide=0.3020
Weight of Magnesium =0.1820
Weight of oxygen =0.3020–0.1820=0.12
Ratio of magnesium: oxygen=0.1820:0.12=1.552:1
In both experiments the ratio of magnesium: oxygen is same (1.518:1)
Hence, it illustrates the law of definite proportions.
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