Question:
calculate the total no. of electron and proton in 1.8÷100 gram of water
Answer:
1.8 / 100 = 0.018 gm
Electrons in 1 water (H2O) molecule = 1(H) + 1(H) + 8(O) = 10 electrons
Thus, in 1 mole, or 18 gms of water, no. of molecules = 6.023 x 1023 molecules.
Therefore, no. of electrons in 1 mole, or 18 gms of water molecules = 6.023 x 1023 x 10
= 6.023 x 1024 electrons
Therefore, in 0.018 gm, it is (6.023 x 1024 x 0.018) /18 electrons
That is, 6.023 x 1021 electrons.
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