

1 mole of sodium acetate is:
Na: 22.99 = 22.99g
H3: 1.01 * 3 = 3.03g
C: 12.01 * 2 = 24.02g
O: 16.00 * 2 = 32.00g
= 82.04g/mol
So 82.04g of compound required to make 1mol/L
Only 0.375Mol/L conc required = 0.375 x 82.04 = 30.765g of compound to make 1L of 0.375M conc.
30.765g of sodium acetate = 0.375 moles
