Question:
A 0.02M solution of pyridinium hydrochloride has pH = 3.44. Calculate the ionization constant of pyridine.
Answer:
pH = -log[H+]
[H+] = 3.63 x 10-4
Then, Kh = 3.63 x 10-4/0.02 = 6.63 x 10-5
Kh = Kw/ Ka = 10-4/6.63 x 10-5 = 1.51 x 10-9
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