Question:
In order to produce an image with magnification m, a concave mirror of focal length f is used. If the object is kept at a distance d from the mirror, then ( m 1)f equals
Answer:
From mirror equation-
Magnification, m= Image height / object height = -(image distance)/object distance .......(1)
and as we know, 1/f = 1/object distance + 1/image distance ........(2)
Given,object distance is d and focal length is f.
From eq. (2)
1/image distance = (d-f) /f.d
So, image distance = f.d /d-f
On putting this value of image distance in eq. (1),we get
m = -(f.d) /d(d-f)
Therefore, (m+1)f = ([-f.d/d(d-f)]+1).f
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