Question:
Find the position and size of the virtual image formed when a 2 cm tall object placed 20 cm from a diverging lens of focal length 40 cm.
Answer:
Using lens formula, 1/f =1/v-1/u
Given, f= 40 cm
u=20 cm
height of object h1= 2 cm
So, 1/40=1/v-1/20
v=40/3 cm (position of image)
Now, using magnification formula we will find the height or size of the image.
magnification m= size of image/size of object = h2/h1 =v/u
So, h2= 80/60= 4/3 cm (size of image)
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