

Given, object distance, u= 10 cm
Focal length, f = 20 cm
We can clearly see here that the focal length is larger than the object distance.
That means the position of object is between Focus F and optical centre of lens O.
Suppose,AB is the object placed between F and O as in below figure.

From lens formula-
1/f = 1/v -1/u
1/v = 3/20
and image distance, v = 20/3 cm.
And the image is virtual,erect in the nature.Larger than the object and formed behind the object,as in figure.
