Question:
An object is placed at a distance of 10 cm from a onvex mirror of focal length 15 cm. Find the position and nature of the image.
Answer:
Object distance (u) = -10 cm
Focal length (f) = 15 cm
image distance (v) = ?
We know, 1/f = 1/v +1/u
or, 1/15 = 1/v + (-1/10)
or, 1/v = 1/15 - 1/10 = 6
So, we can say, image is located at a distance 6m from the mirror on the other side of the mirror.
So, magnificent, m = -v/u = 6/10 = 0.6
The nature of the image is virtual, diminished.
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