learnohub
Question:
Sometimes it is observed that both parents are normal. But they have a colour-blind son. Explain how this is possible with the help of a chess.
Answer:

Both parents may be normal in phenotype, but htey may be carriers of the abnormality. Let us take an example of colour blindness. The red/green colour blindness which is sex linked and recessive i.e. the allele is carried on the non homologous portion of the X sex chromosome.

Since both parents are normal, it means that the mother is heterozygous i.e a carrier XCXc and the father XCY.
The son inherits his X chromosome from his mother and in this case received the X chromosome with the recessive allele.
Parental Phenotype Mother Father

Parental genotype of mother - XCXc

Parental genotype of father - XCY 

Parental gametes XC Xc XC Y

Offspring genotype XC XC XCY XCXc XcY

This shows a probability of 1 in 4 (25 %) of the child being colour blind.

Not what you are looking for? Go ahead and submit the question, we will get back to you.

learnohub

Classes

  • Class 6
  • Class 7
  • Class 8
  • Class 9
  • Class 10
  • Class 11
  • Class 12
  • ICSE 6
  • ICSE 7
  • ICSE 8
  • ICSE 9
  • ICSE 10
  • NEET
  • JEE

YouTube Channels

  • LearnoHub Class 11,12
  • LearnoHub Class 9,10
  • LearnoHub Class 6,7,8
  • LearnoHub Kids

Overview

  • FAQs
  • Privacy Policy
  • Terms & Conditions
  • About Us
  • NGO School
  • Contribute
  • Jobs @ LearnoHub
  • Success Stories
© Learnohub 2026.