learnohub
Question:
Two resistors 4 ohm and 6 ohm are connected in parallel. the combination is connected across a 6 volt battery of negligible resistance. calculate - 1.the current through the battery 2. current through each resistor.
Answer:

(1) V= 6V 

Req = 1/R+ 1 /R2  = 1/4 + 1/6 = 5/12 = 12/5 ohm = 2.4 ohm

According to ohms law ,

V = IR 

I = V/R 

I = 6/2.4

I = 2.5 A

(2)

 i)Current through 6 ohm

 V = 6 V  , R= 6 ohm , I = ?

I = V/R 

I = 6/6 

I = 1 A

ii) Current through 4 ohm

V = 6V , R = 4 ohm , I = ?

I = V/R 

I = 6 /4 

I = 1.5 A 

Not what you are looking for? Go ahead and submit the question, we will get back to you.

learnohub

Classes

  • Class 6
  • Class 7
  • Class 8
  • Class 9
  • Class 10
  • Class 11
  • Class 12
  • ICSE 6
  • ICSE 7
  • ICSE 8
  • ICSE 9
  • ICSE 10
  • NEET
  • JEE

YouTube Channels

  • LearnoHub Class 11,12
  • LearnoHub Class 9,10
  • LearnoHub Class 6,7,8
  • LearnoHub Kids

Overview

  • FAQs
  • Privacy Policy
  • Terms & Conditions
  • About Us
  • NGO School
  • Contribute
  • Jobs @ LearnoHub
  • Success Stories
© Learnohub 2026.