


Consider the above circuit and calculate the effective resistance between P and Q.
ð‘…1 = 1Ω, ð‘…2 = 7Ω, ð‘…3 = 3Ω, ð‘…4 = 6Ω, ð‘…5 = 4Ω.
Resistors ð‘…2 and ð‘…3 are connected in series,
so , ð‘…23 = ð‘…2 + ð‘…3 = 7Ω + 3Ω = 10Ω.
Resistors ð‘…4 and ð‘…5 are connected in series,
so, ð‘…45 = ð‘…4 + ð‘…5 = 6Ω + 4Ω = 10Ω.
We have the parallel connection of ð‘…1, ð‘…23 and ð‘…45, thus
1/ ð‘…ð‘ƒð‘„ = 1 /ð‘…1 + 1/ ð‘…23 + 1/ ð‘…45 = 1/ 1Ω + 1 /10Ω + 1/ 10Ω = 12 /10Ω
ð‘…ð‘ƒð‘„ = 10Ω /12 = 5/ 6 Ω ≈ 0.83Ω.
