Question:
A parallel combination of three resistors takes a current of 7.5 ampere from a 30 volt supplies.If the two resistors , are 10 ohm and 12 ohm , find the third one.
Answer:
Given, voltage = 30 V
Current = 7.5 amp
two resistors of resistance 10 and 12 ohm.
Let the third unknown resistor is Runknown.
From the Ohms law-
V=IR
So,R= V/I
R= 30/7.5 = 4 Ω
Where R is the equivalent resistance
Three resistors are in parallel combination -
1/4 = 1/10 + 1/12 + 1/Runknown
1/Runknown = 1/15
and Runknown = 15 Ω
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