Question:
A combination consists of three resistors in series. Four similar sets are connected in parallel . If the resistance of each resistor is 2 ohm , find the resistance of this combination .
Answer:
There are four sets of resistors in parallel, each set consist of three resistors of 2 Ω.
Equivalent resistance of first set= 2+2+2 = 6 Ω (Three resistors are in series)
Similarly, resistance of 2nd , 3rd and 4th set are, 6Ω ,6Ω and 6 Ω
So, equivalent resistance of network = (1/6)+(1/6)+(1/6)+(1/6)
= 3/2 Ω (Four sets are in parallel)
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