Question:
an equilateral triangle a b c. d is a point on side b c such that b d =1/3 bc prove that 9 ad square= 7 ab square
Answer:
From the figure, AD = a√3/2
and DE = a/6
Now, in triangle ADE,
AD2 = AE2 + DE2
=> AD2 = 3a2 /4 + a2 /36
=> AD2 = 28a2 /36
=> AD2 = 7a2 /9
=> 9AD2 = 7a2
=> 9AD2 = 7AB2
Not what you are looking for? Go ahead and submit the question, we will get back to you.
