Question:
Two poles of heights 6 m and 11 m stand on a plane ground. If the distance between the feet of the poles is 12 m, find the distance between their tops.
Answer:
Let BD is the first pole of height 6m and AE is the second pole of height 11m
Since BD = CE
So CE = 6m
Again BC = DE = 12 m
Now in triangle ABC,
AB2 = AC2 + BC2
=> AB2 = 52 + 122
=> AB2 = 25 + 144
=> AB2 = 169
=> AB = √169
=> AB = 13
So distance between top of the poles = 13 m
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