Question:
Sir is there a formula like AD/AC = CE/BE for a triangle ABC for BPT theorem?
Answer:
Basic Proportional Theorem:
This theorem says that a line parallel to on side of a triangle divides the other two sides into parts of equals proportional.
Let ABC is a triangle and there is a line drawn parallel to BC cuts AB and AC at D and E respectively.
So AD/DB = AE/EC
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