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Question:
thea raea of the base of a right circular cylinder is 17600cm2.its volume is 140800cm2 .find the area of curved surface of the cylinder
Answer:

Right circular cylinder:

A right circular cylinder is a three-dimensional object with two congruent circles as parallel bases and a lateral

surface consisting of a rectangle.

Base and side: The bases of a right circular cylinder are always congruent and parallel to each other.

Height: The height h is the perpendicular distance between the bases.

Radius: The radius r of a cylinder is the radius of a base.

Now, given, area of the base of a right circular cylinder is 17600 cm2

=> 2πr2 = 17600     {Since there are two bases}

=> r2 = 17600/2π

=> r2 = 17600/{(22*2)/7}

=> r2 = (17600*7)/44

=> r2 = 400*7

=> r2 = 2800

=> r = √(2800)

=> r = √(4*7*100)

=> r = 2*10√7

=> r = 20√7

Again, given volume of cylinder = 140800

=> πr2 h = 140800

=> π * 2800* h = 140800

=> h = 140800/(π * 2800)

=> h = 1408/(π * 28)

=> h = 1408/(22/7 * 28)

=> h = 1408/(22 * 4)

=> h = 1408/88

=> h = 16

Now, curved surface area of the cylinder = 2πrh

                                                               = 2 * (22/7) * 20√7 * 16

                                                               = (2 * 22 * 20√7 * 16)/7

                                                               = (14080√7)/7 cm2

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