Given that the water is flowing at the rate of 5 km/hr through a pipe of diameter 14 cm into a rectangular tank which is 50 m long and 44m wide.

Let the level of the water in the tank rise by 7 cm in x hours.

Again the water is flowing at the rate of 5 km/hrSo, the length of the 

So, the length of the water in x hours = 5x km = 5x * 1000 = 5000x m

Here, the water forms a cylinder having radius r = 14/2 = 7 cm = 7/100 m

and length h = 5000x m

Now, the volume of the water flowing through the cylindrical pipe in x hours = πr² h

                                                                                                           = (22/7)*(7/100)² *5000x

                                                                                                           = (22*7*7*5000x)/(7*100*100)

                                                                                                           = (22*7*5x)/10

                                                                                                           = (22*7*x)/2

                                                                                                           = 11*7*x

                                                                                                           = 77x

Now, volume of the water that falls into the tank in x hours = (50*44*7)/100 = (44*7)/2 = 22*7 = 154

Now, volume of the water flowing through the cylinder pipe in x hours = volume of the water that falls in the tank in x hours

=> 77x = 154

=> x = 154/77

=> x = 2

So, the level of water in the tank will rise by 7 cm in 2 hours.