Question:
what is he angle of elevation of the sun when the length of the shadow of a verticle pole is equal to its height
Answer:
Let angle of elevation = θ
Again length of shadow of vertical pole = height of the pole
So AB = BC
Now in triangle ABC,
tanθ = AB/BC
=> tanθ = 1 (Since AB = BC)
=> tanθ = tan 45°
=> θ = 45°
So angle of elevation = 45°
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