Question:
trignometric ratios
Answer:
Let AB is Perpendicular , BC is base and AC is hypotenuse in a triangle ABC
Then
sinθ = Perpendicular/hypotenuse = AB/AC
cosθ = Base/hypotenuse = BC/AC
tanθ = Perpendicular/Base = AB/BC
cosecθ = hypotenuse/Perpendicular = AC/AB
secθ = hypotenuse/ Base = AC/BC
cotθ = Base/Perpendicular = BC/AB
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