Question:
the men on other side of the temple of 30 meter height observe its top at the angle of elevation 30 degrees and 60 degrees respectively.find the distance between the two ends
Answer:
From figure,
In ΔACD
tan 30 = CD/AC
1/√3 = 30/AC
=> AC = 30√3
Again in ΔBCD,
tan 60 = CD/BC
=> √3 = 30/BC
=> BC = 30/√3
=> BC = 30√3/(√3*√3)
=> BC = 30√3/3
=> BC = 10√3
Now,
AB = AC + BC
=> AB = 30√3 + 10√3
=> AB = 40√3
So the distance between the two ends is 40√3 m.
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