Question:
a tower stands vertically on the ground.From a point which is 15m away from the foot of the tower, the angle of elevation of the tower is 45.what is the height of the tower
Answer:
Let AB is the height of the tower.
Now in triangle ABC
tan 45° = AB/BC
=> 1 = AB/15 (BC =15 and tan 45° = 1)
=> AB = 15
So height of the tower = 15 m
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