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Question:
The deck of a ship is 10 metre high from water level.Standing on the deck Anu saw the top of a light house at an angle of elevation 60° and bottom at an angle of depression 30° . Find the height of the light house.
Answer:

Let AE is the height of the light house.

Again BD = CE = 10

Then AE  = AC + CE

 => AE = AC + 10

Now from triangle BED 

tan 30 = BD/DE

=> 1/√3 = 10/DE

=> DE = 10√3

Since BC = DE

So BC = 10√3

Again from triangle ABC,

tan 60  = AC/BC

=> √3 = AC/10√3

=> AC = 10√3*√3

=> AC = 10*3

=> AC = 30

Now AE = AC + 10

=> AE = 30 + 10

=> AE = 40

So height of the light house is 40 m 

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