Question:
The angle of elevation of the top of a tower from a point on the ground, which is 30 m away from the foot of the tower, is 30 degree . Find the height of the tower.
Answer:
Let AB is the height of the tower.
Given angle of elevation = 30
Now in the triangle ABC,
tan 30 = AB/BC
=> 1/√3 = AB/30
=> AB *√3 = 30
=> AB = 30/√3
=> AB = (30*√3)/(√3 *√3) (Multiply by √3 in numerator and denominator)
=> AB = (30*√3)/3
=> AB = 10*√3 m
So height of tower is 10*√3 m
Not what you are looking for? Go ahead and submit the question, we will get back to you.
