Question:
13. The horizontal distance between two towers is 80 m. The angle of depression of the top of the first tower when seen from the top of the second tower is 30o. If the height of the second tower is 160 m, find the height of the first tower.
Answer:
From the figure, height of second tower = AC + CE
= AC + 160 (CE = 160)
Now in Δ ABC,
tan 30° = AC/BC
=> 1/√3 = AC/80
=> AC* √3 = 80
=> AC = 80/√3
=> AC = (80*√3)/(√3*√3)
=> AC = (80*√3)/3
So height of first tower = AC+CE
= (80*√3)/3 + 160 m
Not what you are looking for? Go ahead and submit the question, we will get back to you.
