Question:
log x-y/4=1/2(logx logy).find the value of x/y y/x
Answer:
Given, log (x - y)/4 = (1/2) * (log x + log y)
=> log (x - y)/4 = (1/2) * log (x*y)
=> log (x - y)/4 = log (x*y)1/2
=> (x - y)/4 = (xy)1/2
Take square on both side, we get
=> (x - y)2 /16 = xy
=> (x2 + y2 - 2xy)/16 = xy
=> (x2 + y2 - 2xy)/xy = 16
=> x2 /xy + y2 /xy - 2xy/xy = 16
=> x/y + y/x - 2 = 16
=> x/y + y/x = 16 + 2
=> x/y + y/x = 18
Not what you are looking for? Go ahead and submit the question, we will get back to you.
