Question:
if the sum of the LCM of two numbers is 1260 and their LCM ic 900 more than their HCF,their product is
Answer:
Let a is the LCM and b is the HCF of two numbers.
Given, a + b = 1260 ..............1
and a = b + 900 ...............2
Put value of a in equation 1, we get
b + 900 + b = 1260
=> 2b + 900 = 1260
=> 2b = 1260 - 900
=> 2b = 360
=> b = 360/2
=> b = 180
From equation 1, we get
a + 180 = 1260
=> a = 1260 - 180
=> a = 1080
So, LCM = a = 1080
and HCF = b = 180
Now, product of two numbers = LCM * HCF
=> product of two numbers = 1080 * 180
=> product of two numbers = 194400
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