Question:
if a=2*3, b=2*3*5, c=3n*5 then the LCM (a.b.c)= 2*3 * 3*2 * 5 .find the value of n?
Answer:
Correct question is:
if a = 2*3, b = 2*3*5, c = 3n *5 and the LCM (a,b,c)= 2 * 3 * 3 * 5
Then find the value of n?
Solution:
Given,
a = 2 * 3
b = 2 * 3 * 5
c = 3n * 5
Now, LCM (a,b,c) = 2 * 3 * 3 * 5
=> 2 * 3n * 5 = 2 * 3 * 3 * 5
=> 2 * 3n * 5 = 2 * 32 * 5
=> n = 2
So, the value of n is 2
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