

1. Any odd positive integer is of the form 2q + 1, where q is some integer.
Let x = 2n + 1 and y = 2m + 1, where m and n are some integer.
Now, x2 + y2 = (2n + 1)2 + (2m + 1)2
=> x2 + y2 = 4n2 + 4n + 1 + 4m2 + 4m + 1
=> x2 + y2 = 4(n2 + m2 + n + m) + 2
=> x2 + y2 = 4p + 2, where p = n2 + m2 + n + m
=> Since 4p and 2 are even numbers, So 4p + 2 is an even number.
=> x2 + y2 is an even number and leaves the remainder when divided by 4
=> So, x2 + y2 is an even but not divisible by 4
6. HCF of two numbers is a factor of the LCM of thoses numbers.
Thus, we can not have two numbers whose HCF is 16 and LCM is 380
This is because when we divide 380 by 16, we get a remainder of 12
Thus 16 is not a factor of 380
So, we can not have two numbers whose HCF is 16 and LCM is 380
7. First, we find the LCM of 35, 56 and 91
35 = 5 * 7
56 = 2 * 2 * 2 * 7
91 = 7 * 13
LCM(35, 56, 91) = 2 * 2 * 2 * 5 * 7 * 13 = 3640
Now, add 7 to this number, we get 3647
So, the required number is 3647
NOTE: Please DO NOT ask multiple parts in one questions.
Please ask the remaining questions as separate questions.
Thanks!
