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Question:
x(cube)-19x-30 solve for equation.
Answer:

Given x3 - 19x - 30

Now we will check which value 1, 2, 3 or -1, -2, -3 satisfy the equation.

we will put one by one.

Now x = -2 satisfied the equation

i.e. (-2)3 - 19*(-2) - 30 = 0

=> -8 + 38 - 30 = 0

=> -38 + 38 = 0

=> 0 = 0

 

So  (x+2) is a factor.

Now we will divide x3 - 19x - 30 by (x+2), we get  (x2 - 2x - 15)

Now

      x2 - 2x - 15 = 0

 

=> x2 - 5x + 3x - 15 = 0 

=> (x-5)*(x+3) = 0

=> x = 5, -3 

So factors of x3 - 19x - 30 are (x-5) and (x+3) and (x+2).

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