Question:
x2-2ax a2-b2=0 solve it by factorization method and please intepret me
Answer:
Given, x2 - 2ax + a2 - b2 = 0
=> (x - a)2 - b2 = 0 {since x2 - 2ax + a2 = (x - a)2 }
=> (x - a - b)*(x - a + b) = 0 {since a2 - b2 = (a - b)*(a + b)}
=> x - a - b = 0 and x - a + b = 0
=> x = a + b, a - b
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