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Question:
if roots of x² - mx 12 = 0 are in ratio 1:3 , then find m.
Answer:

Given equation is: x2 - mx + 12 = 0

Let roots of the equations are a and b

Given a : b = 1 : 3

=> a/b = 1/3

=> 3a = b .............1

Now, a + b = m

=> a + 3a = m

=> 4a = m .................2

and a * b = 12 ..........3

=> a * 3a = 12

=> 3a2 = 12

=> a2 = 12/3

=> a2 = 4

=> a = ±√4

=> a = ±2

From equation 2

      m = 4 * (±2)

=> m = ±8

So, the value of m is  ±8

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