

Given equation is: x2 - mx + 12 = 0
Let roots of the equations are a and b
Given a : b = 1 : 3
=> a/b = 1/3
=> 3a = b .............1
Now, a + b = m
=> a + 3a = m
=> 4a = m .................2
and a * b = 12 ..........3
=> a * 3a = 12
=> 3a2 = 12
=> a2 = 12/3
=> a2 = 4
=> a = ±√4
=> a = ±2
From equation 2
m = 4 * (±2)
=> m = ±8
So, the value of m is ±8
