Question:
What is the value of x2 3x 5by completing the square method
Answer:
Given, x2 + 3x + 5
Now, take 1/2 of the coefficient of x, square it.
Now, add and subtract this value in the polynomial, we get
=> x2 + 3x + (3/2)2 + 5 - (3/2)2
=> x2 + 3x + 9/4 + 5 - 9/4
=> x2 + 3x + 9/4 + (4*5 - 9)/4
=> (x + 3/2)2 + (20 - 9)/4
=> (x + 3/2)2 + 11/4
=> (x + 3/2)2 + (± √11/2)2
=> (x + 3/2 + √11/2)*(x + 3/2 - √11/2)
So, x2 + 3x + 5 = (x + 3/2 + √11/2)*(x + 3/2 - √11/2)
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