Question:
The Perimeter of a rectangle is 40 meters. If the lenght is increseased by 3 meters and breadth is decreased by 2 meters, the area is decreased by 6 meter square. Find the dimensions of rectangle.
Answer:
Let the length of the rectangle is x and breadth is y.
Given perimeter of the rectangle = 40
=> 2(x + y) = 40
=> x + y = 40/2
=> x + y = 20 ...............1
Area of the rectangle = x*y
Agaian given in the question
length is increased by 3
So length= x+3
and breadth decreased by 2
So breadth= y-2
area is decreased by 6
So (x+3)(y-2)= xy-6
=> xy - 2x + 3y - 6 = xy - 6
=> - 2x + 3y = 0
=> 2x - 3y = 0 .............2
On solving this equation 1 and 2
x= 12 and y= 8
Hense length of the rectangle is 12 and breadth is 8.
Not what you are looking for? Go ahead and submit the question, we will get back to you.
