Question:
Question 2: If the sum of the roots of the equation x2 - (k+6)x + 2(2k - 1) = 0 is equal to half of their product, then k =
Answer:
Given equation is: x2 - (k+6)x + 2(2k - 1) = 0
Now, sum of the root = k + 6
Product of the root = 2(2k - 1)
Given, sum of the roots = half of the product of the root
=> k + 6 = 2(2k - 1)/2
=> k + 6 = 2k - 1
=> 2k - k = 6 + 1
=> k = 7
So, the value of k is 7
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