Question:
For what value of k, the quadratic equation x2 - kx + 4 = 0 has equal roots?
Answer:
Given, equation is x2 - kx + 4 = 0
Given, roots are equal, so its discriminant value will be equal to zero
=> D = 0
=> b2 - 4ac = 0 .............1
On comapring the given equation with ax2 + bx + c = 0, we get
a = 1, b = -k, c = 4
From equation 1, we get
=> (-k)2 - 4 * 1 * 4 = 0
=> k2 - 16 = 0
=> k2 = 16
=> k = ±√16
=> k = ±4
So, the value of k is k = ±4
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