Question:
Find the value of k, for which one root of the quadratic equation kx2 -14x 8=0 is six times the other.
Answer:
Given equation is : kx2 -14x + 8 = 0
Let first root = x
Then the second root = 6x
Now, sum of the roots = 14
=> x + 6x = 14
=> 7x = 14
=> x = 14/7
=> x = 2
Again, product of the roots = 8/k
=> x * 6x = 8/k
=> 2*6*2 = 8/k
=> 24 = 8/k
=> k = 8/24
=> k = 1/3
So, the value of k is 1/3
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