Question:
2xsquare +16x +3=0 find the roots of this equation by factorisation method
Answer:
Given, 2x2 + 16x + 3 = 0
We can not find the roots by using factorisation method.
We use another method to find the roots of the equation.
Now, x = [-16 ± √{(16)2 - 4 * 2 * 3}]/(2 * 2)
=> x = [-16 ± √{256 - 24}]/4
=> x = [-16 ± √232]/4
=> x = [-16 ± √{2 * 2 * 2 * 29}]/4
=> x = [-16 ± 2√{2 * 29}]/4
=> x = [-16 ± 2√58]/4
=> x = [-8 ± √58]/2
Hence, the roots of the equation are (-8 + √58)/2 and (-8 - √58)/2
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