Question:
a bag contains 5 red balls and some blue balls. if the probability of drawing a blue ballis double that of a red ball how many blue balls are there?
Answer:
Let number of blue balls be b
Number of red balls = 5
Total number of balls = 5 + b
Probability of picking a red ball, P(R) = 5/(5 + b)
Probability of picking a blue ball, P(B) = b/(5 + b)
Given,
P(B) = 2P(R)
=> b/(5 + b) = 2{5 / (5 + b)}
=> b/(5 + b) = 10 / (5 + b)
=> b = 10
So, the number of blue balls in the bag = 10
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